The near and far faces appear to be trapezoids, with bases 12 in and 8 in and height 8 in. Hence each of them has an area .. Atrapezoid = (1/2)(b1 +b2)h .. = (1/2)(12 in + 8 in)*(8 in) .. = 80 in^2
The remaining faces unroll into a rectangle 8 in wide and (12 +8 +8+9) in long. The area of a rectangle is the product of its length and width. .. Arectangle = length*width .. = (37 in)*(8 in) = 296 in^2
The total surface area is the sum of the rectangle area and the two trapezoidal faces. .. Atotal = Arectangle + 2*Atrapezoid .. = 296 in^2 +2*80 in^2 .. = 456 in^2
