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If it takes 6.02 kj of heat energy to melt a mole of ice, how much heat is absorbed when 6.30 g of water melts? 21.0 j 2.10 kj 21 kj 0.210 kj

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skyluke89
First, let's see how many moles correspond to 6.30 g of water.
The molar weight of water is 18.01 g/mol, so
[tex]n= \frac{6.30 g}{18.01 g/mol}=0.35 mol [/tex]
Then we know it takes 6.02 kJ to melt 1 mole of ice, so if we have 0.35 mol, the amount of heat needed will be
[tex]Q=6.02 kJ \cdot 0.35 mol=2.10 kJ[/tex]

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