Yayita21
Yayita21
11-04-2018
Mathematics
contestada
can someone plz help me thank you
Respuesta :
iGreen
iGreen
11-04-2018
7.
Direct variation is:
[tex]\sf y=kx[/tex]
Where 'k' is the constant of variation. Let's plug in y = -6 and x = 10 into the formula:
[tex]\sf -6=k(10)[/tex]
Divide 10 to both sides:
[tex]\sf k=-\dfrac{3}{5}[/tex]
Plug this in for 'k' in our formula:
[tex]\sf y=-\dfrac{3}{5}x[/tex]
This is our formula. To find out what 'y' is when 'x' = 5, plug in 5 for 'x':
[tex]\sf y=-\dfrac{3}{5}(5)[/tex]
Multiply:
[tex]\boxed{\sf y=-3}[/tex]
9.
Let's plug in y = 9 and x = 8 into our formula:
[tex]\sf 9=k(8)[/tex]
Divide 8 to both sides:
[tex]\sf k=\dfrac{9}{8}[/tex]
So our equation is:
[tex]\sf y=\dfrac{9}{8}x[/tex]
Now let's plug in 18 for 'y' to find out what 'x' is when y = 18:
[tex]\sf 18=\dfrac{9}{8}x[/tex]
Divide 9/8 to both sides or multiply by its reciprocal 8/9:
[tex]\sf x=18\cdot\dfrac{8}{9}\rightarrow \boxed{\sf 16}[/tex]
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