A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance? 1.7 × 106 joules 3.4 × 106 joules 5.6 × 106 joules 6.8 × 106 joules
Work done = Force x displacement = mass x acceleration x displacement               = 7000 x 0.0083 x 5.4 x 10^4 = 3.369 x 10^6 Joules ~ 3.4 x 10^6 J
