jetblackcap jetblackcap
  • 14-04-2018
  • Mathematics
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Please help me!!!!!!!!!!

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Аноним Аноним
  • 14-04-2018
If this equation is perpendicular to y = 2/3*x - 1 and its gradient is denoted by m, then:
m*2/3 = -1
m = -3/2

Now using the point (4,7) and m = -3/2:
y - y1 = m(x - x1)
y - 7 = -3/2(x - 4)
y = -3/2x + 6 + 7
y = -3/2x + 13
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